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5.2x^2+5.6x=0
a = 5.2; b = 5.6; c = 0;
Δ = b2-4ac
Δ = 5.62-4·5.2·0
Δ = 31.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5.6)-\sqrt{31.36}}{2*5.2}=\frac{-5.6-\sqrt{31.36}}{10.4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5.6)+\sqrt{31.36}}{2*5.2}=\frac{-5.6+\sqrt{31.36}}{10.4} $
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